Answer :
Final answer:
To calculate the mass of hydrochloric acid needed to prepare chlorine gas, we need to determine the molar ratio of HCl to Cl2 and use stoichiometry. The correct answer is D) 142.0 g.
Explanation:
To calculate the mass of hydrochloric acid needed to prepare 150.0 g of chlorine gas, we need to determine the molar ratio of HCl to Cl2. From the balanced chemical equation:
2 HCl(aq) + Cl2(g) → 2 Cl2(g)
we can see that 2 moles of HCl are required to produce 1 mole of Cl2. Since the molar mass of Cl2 is 70.91 g/mol, we can calculate the mass of HCl using the formula:
mass of HCl = (moles of Cl2) x (molar mass of HCl)
By substituting the values, we get:
mass of HCl = (150.0 g Cl2) x (2 mol HCl / 1 mol Cl2) x (36.46 g/mol HCl) = 10,939.8 g HCl
Therefore, the correct answer is D) 142.0 g.
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