Answer :
The Final velocity right after a 116 kg rugby player who is initially running at 7.15 m/s is 856.90 m/s
To calculate the final velocity of the rugby player after colliding with the goalpost, we can use Newton's second law of motion and the equation for impulse.
Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
F = m * a
In this case, the net force is the backward force experienced by the rugby player when colliding with the goalpost. The acceleration can be calculated using the equation for impulse:
J = F * Δt
Where:
J is the impulse (change in momentum)
F is the force
Δt is the time interval
The impulse is also equal to the change in momentum:
J = m * Δv
Where:
m is the mass of the rugby player
Δv is the change in velocity
Combining these equations, we have:
m * Δv = F * Δt
Rearranging the equation to solve for Δv:
Δv = (F * Δt) / m
Now we can plug in the given values:
m = 116 kg (mass of the rugby player)
F = 18100 N (backward force experienced)
Δt = 5.50 × 10^(-2) s (time interval)
Δv = (18100 N * 5.50 × 10^(-2) s) / 116 kg
Δv ≈ 856.90 m/s
Therefore, the final velocity of the rugby player, right after colliding with the goalpost, is approximately 856.90 m/s in the backward direction.
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