College

Calculate the approximate induced stress (in psi) on a rectangular section helical steel compression spring loaded with 235 lb. The spring's thickness (t) is 0.3 in., the width (b), parallel to the spring's axis, is 0.6 in., and the mean coil diameter is 1.8 in. Round your answer to four significant figures.

Answer :

he approximate induced stress on the rectangular section helical steel compression spring is approximately 1305.5556 psi (rounded to 4 significant figures).

To calculate the induced stress on a rectangular section helical steel compression spring, we can use the formula:

Stress = (F / A) + (M × c / I)

Where:

Stress is the induced stress on the spring

F is the applied force on the spring

A is the cross-sectional area of the rectangular section

M is the bending moment due to the rectangular section

c is the distance from the neutral axis to the extreme fiber of the rectangular section

I is the moment of inertia of the rectangular section

First, let's calculate the cross-sectional area (A) of the rectangular section:

A = t × b

Given that the thickness (t) is 0.3 in and the width (b) is 0.6 in:

A = 0.3 in × 0.6 in

A = 0.18 in²

Next, we need to calculate the moment of inertia (I) of the rectangular section:

I = (t × b^3) / 12

Given the values of t and b:

I = (0.3 in × (0.6 in)^3) / 12

I = 0.0054 in^4

The distance from the neutral axis to the extreme fiber (c) can be assumed to be half the thickness of the rectangular section:

c = t / 2

c = 0.3 in / 2

c = 0.15 in

Now, we can calculate the bending moment (M) due to the rectangular section:

M = F × (mean coil diameter / 2)

Given that the applied force (F) is 235 lb and the mean coil diameter is 1.8 in:

M = 235 lb × (1.8 in / 2)

M = 211.5 lb·in

Finally, we can calculate the induced stress (Stress):

Stress = (F / A) + (M × c / I)

Stress = (235 lb / 0.18 in²) + (211.5 lb·in × 0.15 in / 0.0054 in^4)

Stress ≈ 1305.5556 psi (rounded to 4 significant figures)

Therefore, the approximate induced stress on the rectangular section helical steel compression spring is approximately 1305.5556 psi (rounded to 4 significant figures).

To know more about moment of inertia :

brainly.com/question/14460640

#SPJ11