Answer :
To determine the tension developed in cable ABC required for the equilibrium of the 143-kg sack, we need to consider the forces acting on the sack and apply the principle of equilibrium.
First, let's draw a free-body diagram of the forces acting on the sack:
where T is the tension in cable ABC.
The weight of the sack (W) is given by:
W = m*g
where m is the mass of the sack and g is the acceleration due to gravity (9.8 m/s^2).
W = 143 kg * 9.8 m/s^2 = 1397.4 N
Since the sack is in equilibrium, the sum of the forces acting on it in the vertical direction must be zero:
T - W = 0
T = W = 1397.4 N
Therefore, the tension developed in cable ABC required for the equilibrium of the 143-kg sack is 1397.4 N.
To learn more about gravity, visit here
https://brainly.com/question/4014727
#SPJ4
