By titration, it is found that 66.9 mL of 0.111 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.

A) 0.149 M
B) 0.375 M
C) 0.111 M
D) 0.449 M

Question

High School

Answer :

Bistai12 Bistai12 · Answer 1 · 2024-10-13T04:56:08-04:00

The concentration of the HCl solution is calculated to be 0.297 M. Thus, none of the given options is correct.

Given the titration of 25.0 mL of HCl with 66.9 mL of 0.111 M NaOH, we have the balanced equation:

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

The reaction shows that NaOH and HCl react on a 1:1 molar basis.

We can calculate the moles of NaOH used in the titration:

Moles of NaOH = Volume (L) x Molarity (M)

Moles of NaOH = 0.0669 L x 0.111 M

Moles of NaOH = 0.00743.

Since the amount of HCl is equal to the amount of NaOH that reacted, we have 0.00743 moles of HCl.

To find the concentration of HCl, we use the formula:

Concentration of HCl = Moles of HCl / Volume of HCl solution (L)

Concentration of HCl = 0.00743 moles / 0.025 L

Concentration of HCl = 0.2972 M, which rounds off to 0.297 M.

Hence, the concentration of the HCl solution is 0.297 M.

Therefore, none of the given options is correct.