College

Based on the table below, evaluate [tex]f(2)[/tex] and solve for [tex]x[/tex] when [tex]f(x) = 4[/tex].

\[
\begin{array}{c|cccccccccc}
x & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\
\hline
f(x) & 68 & 27 & 62 & 51 & 20 & 2 & 64 & 52 & 4 & 66 \\
\end{array}
\]

- [tex]f(2) = 62[/tex]
- Solve for [tex]x[/tex] when [tex]f(x) = 4[/tex].

Answer :

Answer: \[f(0) = 0, \quad f(1) = 4, \quad f(2) = 8, \quad f(3) = 12, \quad f(4) = 16, \quad f(5) = 20, \quad f(6) = 24, \quad f(7) = 28, \quad f(8) = 32, \quad f(9) = 36\]

Step-by-step explanation:

To solve the equation \(f(x) = 4x\), you need to substitute the values of \(x\) from the table into the equation and calculate \(f(x)\) for each value. Here are the calculations:

For \(x = 0\):

\[f(0) = 4 \cdot 0 = 0\]

For \(x = 1\):

\[f(1) = 4 \cdot 1 = 4\]

For \(x = 2\):

\[f(2) = 4 \cdot 2 = 8\]

For \(x = 3\):

\[f(3) = 4 \cdot 3 = 12\]

For \(x = 4\):

\[f(4) = 4 \cdot 4 = 16\]

For \(x = 5\):

\[f(5) = 4 \cdot 5 = 20\]

For \(x = 6\):

\[f(6) = 4 \cdot 6 = 24\]

For \(x = 7\):

\[f(7) = 4 \cdot 7 = 28\]

For \(x = 8\):

\[f(8) = 4 \cdot 8 = 32\]

For \(x = 9\):

\[f(9) = 4 \cdot 9 = 36\]

So, the values of \(f(x)\) for each \(x\) in the table are:

\[f(0) = 0, \quad f(1) = 4, \quad f(2) = 8, \quad f(3) = 12, \quad f(4) = 16, \quad f(5) = 20, \quad f(6) = 24, \quad f(7) = 28, \quad f(8) = 32, \quad f(9) = 36\]