College

b. Calculate the horizontal component of the force you apply.

Solution:
\[ \text{Horizontal Component} = 120 \cdot \cos(35^\circ) = 98.2 \, \text{N} \]

c. How does the size of the horizontal component of the force you apply to the lawnmower compare to the size of the frictional force on the lawnmower? Briefly explain why.

The frictional force equals the horizontal component because the lawnmower is moving at a constant speed. The horizontal component of the applied force is equal to the frictional force, resulting in no net force between the two.

d. Write an equation for all of the vertical forces on the lawnmower. This is a statement of Newton's Second Law. You will not have a final answer.

e. Calculate the size of the normal force.

Answer :

Sure, I'd be happy to help explain the solution step by step.

b. Calculate the horizontal component of the force you apply.

To find the horizontal component of a force, you can use the formula:
[tex]\[
\text{Horizontal Force} = \text{Total Force} \times \cos(\text{angle})
\][/tex]
Here, the total force is 120 N, and the angle is 35 degrees. The calculation gives us a horizontal force of approximately 98.3 N.

c. How does the size of the horizontal component of the force you apply to the lawnmower compare to the size of the frictional force on the lawnmower? Briefly explain why.

Since the lawnmower is moving at a constant speed, the horizontal component of the applied force and the frictional force must be equal. This equality occurs because, according to Newton's First Law, an object moving at a constant speed has no net force acting on it. Thus, the horizontal component of the applied force (98.3 N) is equal to the frictional force.

d. Write an equation for all of the vertical forces on the lawnmower.

Vertically, the sum of forces must be zero when the forces are balanced. We can write:
[tex]\[
\text{Normal Force} + \text{Gravitational Force} = \text{Vertical Component of Applied Force}
\][/tex]

e. Calculate the size of the normal force.

To find the normal force, which balances the vertical forces, we need to consider the vertical component of the applied force:
[tex]\[
\text{Vertical Component} = \text{Total Force} \times \sin(\text{angle})
\][/tex]
With a total force of 120 N and an angle of 35 degrees, the vertical component is calculated. Normally, we would also need the gravitational force acting on the lawnmower; however, it isn't provided here, but we assume gravitational force balances out.

The normal force is adjusting to ensure the vertical forces balance, given any gravitational force combined with the vertical force component.

I hope this explanation helps clarify the steps involved in solving this question!