Average age at diagnosis of coronary heart disease in the population is 63.3. In a sample of 22 adults from Marin County, the mean age at diagnosis was 66.9 with a standard deviation of 10.3.

Based on your answer to the previous question, is there statistical evidence of a significantly higher age of diagnosis? Use the 0.05 level.

Options:
A. Yes
B. No
C. Not enough information to tell

There here is not enough statistical evidence to conclude that the mean age at diagnosis in Marin county is significantly higher than the population mean of 63.3.

Given data:

- Population mean (μ) = 63.3

- Sample size (n) = 22

- Sample mean (M) = 66.9

- Sample standard deviation (SD) = 10.3

- Significance level (α) = 0.05

Let's calculate the test statistic (t-statistic) using the formula for a one-sample t-test:

[tex]\[t = \frac{{M - μ}}{{\frac{{SD}}{{\sqrt{n}}}}}\][/tex]

Substitute the values:

[tex]\[t = \frac{{66.9 - 63.3}}{{\frac{{10.3}}{{\sqrt{22}}}}}\][/tex]

[tex]\[t \approx 1.187\][/tex]

Next, at the 0.05 level of significance and degrees of freedom (df) equal to 21 (n - 1).

For a two-tailed test and α = 0.05, the critical t-value is ±2.080.

Now, compare the calculated t-statistic (1.187) to the critical t-value (±2.080):

Since the calculated t-statistic (1.187) is less than the critical t-value (2.080), we fail to reject the null hypothesis (H0).

Learn more about Test Statistic here:

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