Answer :
The speed of the 2000 kg compact car that has the same kinetic energy as a 20000 kg truck going 25 km/hr is approximately 34.6 m/s.
To find the speed of the 2000 kg compact car that has the same kinetic energy as a 20000 kg truck going 25 km/hr, we can use the formula for kinetic energy, which is KE = 1/2 [tex]mv^2[/tex].
First, we need to find the kinetic energy of the 20000 kg truck going 25 km/hr. We convert 25 km/hr to m/s by multiplying by 1000/3600, which gives us 6.94 m/s. Then, we plug in the values into the formula:
KE = 1/2 (20000 kg) [tex](6.94 m/s)^2[/tex] = 959,200 J.
Next, we set this equal to the kinetic energy of the compact car: KE = 1/2 (2000 kg) [tex]v^2[/tex]. We can simplify this equation by dividing both sides by 1/2 (2000 kg), which gives us v^2 = 959,200 J / (1/2) (2000 kg).
Solving for v, we take the square root of both sides: v = √(959,200 J / (1/2) (2000 kg)) = 34.6 m/s.
Therefore, the speed of the 2000 kg compact car that has the same kinetic energy as a 20000 kg truck going 25 km/hr is approximately 34.6 m/s.
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