Answer :
Final answer:
A 1000 kg compact car needs to travel at approximately 111.8 m/s to have the same kinetic energy as a 20,000 kg truck traveling at 25 km/hr.
Explanation:
The kinetic energy (KE) of an object is given by the formula KE = 0.5*m*v², where m is the mass of the object and v is its velocity (speed). Given that we want the compact car to have the same kinetic energy as the truck, we can equate the two equations: 0.5 * 1000 * v² = 0.5 * 20000 * (25/3.6)² (converting km/hr to m/s).
To solve for v, the velocity of the compact car, we first simplify the equation to get: v² = (20000 * (25/3.6)²) / 1000, and finally arriving at the approximate result for v as 111.8 m/s. Therefore, a 1000 kg compact car would need to travel at approximately 111.8 m/s to have the same kinetic energy as a 20000 kg truck traveling at 25 km/hr.
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Final answer:
To find the speed at which a 1000 kg compact car has the same kinetic energy as a 20000 kg truck going at 25 km/h, we can use the equation for kinetic energy: KE = ½ mv². By setting the kinetic energy of the car equal to the kinetic energy of the truck and solving for the velocity, we find that the car would have the same kinetic energy as the truck at approximately 31.03 m/s.
Explanation:
To find the speed at which a 1000 kg compact car has the same kinetic energy as a 20000 kg truck going at 25 km/hr, we can use the equation for kinetic energy: KE = ½ mv². First, we need to convert the speed of the truck to m/s. 25 km/hr = (25 km/hr) * (1000 m / 1 km) / (3600 s/hr) = 6.94 m/s. Now we can calculate the kinetic energy of the truck: KE = ½ (20000 kg) (6.94 m/s)² = 480,560 J.
To find the speed at which the car has the same kinetic energy, we can set the kinetic energy of the car equal to the kinetic energy of the truck and solve for the velocity. ½ (1000 kg) v² = 480,560 J. Simplifying the equation, we get v² = 960. Solution: v ≈ √960 ≈ 31.03 m/s. Therefore, a 1000 kg compact car would have the same kinetic energy as a 20000 kg truck going at approximately 31.03 m/s.
