College

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224 ; x = 196[/tex] pounds
B. [tex]\frac{7}{8} x = 224 ; x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224} ; x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224} ; x = 256[/tex] pounds

Answer :

To solve the problem, we need to find out how much weight Balin could bench press given that Jasper could bench press 224 pounds, which is [tex]\(\frac{7}{8}\)[/tex] of what Balin can press.

Let's break this down step by step:

1. Set up the equation:
We know that [tex]\( \frac{7}{8} \)[/tex] of Balin's bench press amount is 224 pounds. So we can write the equation as:
[tex]\[
\frac{7}{8}x = 224
\][/tex]
where [tex]\( x \)[/tex] is the weight that Balin could bench press.

2. Solve for [tex]\( x \)[/tex]:
To find [tex]\( x \)[/tex], we need to solve the equation. We can do this by multiplying both sides of the equation by the reciprocal of [tex]\(\frac{7}{8}\)[/tex], which is [tex]\(\frac{8}{7}\)[/tex]:
[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

3. Calculate [tex]\( x \)[/tex]:
Now, by multiplying:
[tex]\[
x = 224 \times \frac{8}{7} = 256
\][/tex]

So, Balin could bench press 256 pounds. The correct equation is [tex]\(\frac{7}{8}x = 224\)[/tex] and the value of [tex]\(x\)[/tex] is 256 pounds. Therefore, the correct choice is:
[tex]\[
\frac{7}{8}x=224 \text{ ; } x=256 \text{ pounds}
\][/tex]