College

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x=224; \, x=196[/tex] pounds
B. [tex]\frac{7}{8} x=224; \, x=256[/tex] pounds
C. [tex]\frac{7}{8}=\frac{x}{224}; \, x=196[/tex] pounds
D. [tex]\frac{7}{8}=\frac{x}{224}; \, x=256[/tex] pounds

Answer :

To find out how much weight Balin could bench press, we know that Jasper's bench press was [tex]\(\frac{7}{8}\)[/tex] of Balin's bench press. Here's how we solve for [tex]\(x\)[/tex], the weight that Balin can bench press:

1. Set up the equation: Based on the problem, we have [tex]\(\frac{7}{8} \times x = 224\)[/tex], where 224 pounds is the weight Jasper could bench press.

2. Solve for [tex]\(x\)[/tex]: To isolate [tex]\(x\)[/tex], we need to get rid of the fraction by multiplying both sides of the equation by the reciprocal of [tex]\(\frac{7}{8}\)[/tex]. The reciprocal of [tex]\(\frac{7}{8}\)[/tex] is [tex]\(\frac{8}{7}\)[/tex].

[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

3. Calculate the result: Multiply 224 by [tex]\(\frac{8}{7}\)[/tex].

[tex]\[
x = 224 \times \frac{8}{7} = 256
\][/tex]

Thus, Balin could bench press 256 pounds.

The correct equation and value of [tex]\(x\)[/tex] is:

[tex]\[
\frac{7}{8} x = 224 ; \quad x = 256 \text{ pounds}
\][/tex]