Answer :
Answer: 24.6kpa
Explanation:
This is a classic case where Boyle's Law can be applied.
The equation for Boyle's Law is given as: P1V1 = P2V2
Where P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume
From the question, P1 = ?, P2 = 98.2kpa , V1 =4L , V2 =1L
P1V1 = P2V2
P1 x 4L = 98.2 kpa x 1L
Make P1 subject of formula we then have:
P1 = 98.2kpa X 1L / 4L
= 24.6kpa
