At 2.00 s, the acceleration of a particle in counterclockwise circular motion is (6.00 m/s\(^2\), 4.00 m/s\(^2\)). The particle moves at a constant speed.

At what time does this occur?

A. 2.00 s
B. 4.00 s
C. 6.00 s
D. 8.00 s

The centripetal acceleration is always directed towards the center of the circular path, while the tangential acceleration is perpendicular to the velocity of the particle.

By calculating the magnitudes of these accelerations at t = 2.00 s, we can determine the total acceleration experienced by the particle.

At 2.00 s, the acceleration of a particle in counterclockwise circular motion is (6.00 m/s\(^2\), 4.00 m/s\(^2\)). The particle moves at a constant speed.At what time does this occur?A. 2.00 s B. 4.00 s C. 6.00 s D. 8.00 s

Answer :

Final answer:

Explanation:

Other Questions

At 2.00 s, the acceleration of a particle in counterclockwise circular motion is (6.00 m/s\(^2\), 4.00 m/s\(^2\)). The particle moves at a constant speed.

At what time does this occur?

A. 2.00 s
B. 4.00 s
C. 6.00 s
D. 8.00 s