Answer :
Answer:
The mass of A and B together is 125kg
Explanation:
To solve this problem, we set up the equations expressing the net force acting on A and B (forces acting to the right are +, those acting to the left are -):
[tex]m_B\cdot a_B=F - F_{fr}\\m_A\cdot a_A = F_{fr}\\a_A = a_B[/tex]
The net force acting on B is due to the acting pull force 100N less friction force caused by A. The net force on A is due to the friction force caused by the block B. Since we know both blocks accelerate at the same rate, the system can be solved easily:
[tex](m_B+m_A)\cdot a_B=F\\(m_B+m_A)\cdot 0.800 \frac{m}{s^2}=100N\implies\\m_B+m_A = \frac{100N}{0.800\frac{m}{s^2}}kg= 125kg[/tex]
Of course, alternatively, in this very simple case you could consider A+B a single object being pulled with 100N, and obtain the same results by diving the pull force by the acceleration.
