Answer :
To test the claim that the mean waste generated is more than 44 pounds per person per day, a one-sample z-test is appropriate. The test would require correctly stating the null and alternative hypotheses and calculating the test statistic. Given the typo in the provided data, accurate mean and standard deviation values must be used for the calculations.
The question asks whether the mean waste generated by adults in a country is more than 44 pounds per person per day. With a sample of 99 adults showing a mean of 4.3 pounds and a standard deviation of 1.6 pounds, a hypothesis test at an \(\alpha = 0.05\) significance level is needed to determine if we can support the claim that the mean waste generated is actually more than the 44 pounds claimed.
Using a one-sample z-test:
- Null hypothesis (\(H_0\)): \(\mu \leq 44\) lbs
- Alternative hypothesis (\(H_a\)): \(\mu > 44\) lbs
- Calculate the test statistic using \(\bar{x}\), \(\sigma\), and \(n\).
- Compare the z-value to the critical value corresponding to \(\alpha = 0.05\).
- If the test statistic exceeds the critical value, reject the null hypothesis.
However, there is a typo in the provided data. It's crucial to note that the mean and standard deviation must be corrected to perform the test accurately. Assuming the correct mean is greater than 44 pounds, then proper calculations would need to be made with the corrected figures.