Answer :
To find the average velocity for each leg of Adam's bus trip and arrange the legs from highest to lowest velocity, we can follow these steps:
1. Understanding Average Velocity: Average velocity is calculated by dividing the distance traveled by the time taken. It's given in km/min here.
2. Calculate the Average Velocity for Each Leg:
- Leg A: Distance = 18 km, Time = 9 min.
Average velocity = 18 km / 9 min = 2.0 km/min.
- Leg B: Distance = 25 km, Time = 15 min.
Average velocity = 25 km / 15 min ≈ 1.67 km/min.
- Leg C: Distance = 24 km, Time = 8 min.
Average velocity = 24 km / 8 min = 3.0 km/min.
- Leg D: Distance = 48 km, Time = 12 min.
Average velocity = 48 km / 12 min = 4.0 km/min.
- Leg E: Distance = 15 km, Time = 7 min.
Average velocity = 15 km / 7 min ≈ 2.14 km/min.
3. Arrange the Legs from Highest to Lowest Velocity:
- Leg D: 4.0 km/min
- Leg C: 3.0 km/min
- Leg E: 2.14 km/min
- Leg A: 2.0 km/min
- Leg B: 1.67 km/min
Thus, the legs arranged from highest to lowest velocity are D, C, E, A, and B.
1. Understanding Average Velocity: Average velocity is calculated by dividing the distance traveled by the time taken. It's given in km/min here.
2. Calculate the Average Velocity for Each Leg:
- Leg A: Distance = 18 km, Time = 9 min.
Average velocity = 18 km / 9 min = 2.0 km/min.
- Leg B: Distance = 25 km, Time = 15 min.
Average velocity = 25 km / 15 min ≈ 1.67 km/min.
- Leg C: Distance = 24 km, Time = 8 min.
Average velocity = 24 km / 8 min = 3.0 km/min.
- Leg D: Distance = 48 km, Time = 12 min.
Average velocity = 48 km / 12 min = 4.0 km/min.
- Leg E: Distance = 15 km, Time = 7 min.
Average velocity = 15 km / 7 min ≈ 2.14 km/min.
3. Arrange the Legs from Highest to Lowest Velocity:
- Leg D: 4.0 km/min
- Leg C: 3.0 km/min
- Leg E: 2.14 km/min
- Leg A: 2.0 km/min
- Leg B: 1.67 km/min
Thus, the legs arranged from highest to lowest velocity are D, C, E, A, and B.