Answer the following questions:

Three teams of people volunteered to clean up after a large music festival. Each team was allocated an area and had to report in after 3 hours.

- Team A had cleared [tex]\frac{39}{50} \, \text{m}^2[/tex].
- Team B had cleared [tex]\frac{50}{75} \, \text{m}^2[/tex].
- Team C had cleared [tex]\frac{55}{100} \, \text{m}^2[/tex].

1. Which team had cleared the most of their allocated area?
[tex]\square[/tex]

2. Which team cleared the least?
[tex]\square[/tex]

Let's determine which team cleared the most and the least of their allocated area after 3 hours.

To make this comparison, we'll convert the areas each team cleared into decimal values.

1. Team A: Cleared [tex]\( \frac{39}{50} \)[/tex] of their area.
- Converting to decimal: [tex]\( \frac{39}{50} = 0.78 \)[/tex]

2. Team B: Cleared [tex]\( \frac{50}{75} \)[/tex] of their area.
- Simplifying: [tex]\( \frac{50}{75} = \frac{2}{3} \)[/tex]
- Convert to decimal: [tex]\( 0.6667 \)[/tex] (rounded to four decimal places)

3. Team C: Cleared [tex]\( \frac{55}{100} \)[/tex] of their area.
- Converting to decimal: [tex]\( \frac{55}{100} = 0.55 \)[/tex]

Now, let's compare the decimal values to see which team cleared the most and the least of their areas:

- Most Cleared Area:
- Team A cleared [tex]\( 0.78 \)[/tex], which is the highest among the three teams.
- So, Team A cleared the most of their allocated area.

- Least Cleared Area:
- Team C cleared [tex]\( 0.55 \)[/tex], which is the smallest among the three teams.
- So, Team C cleared the least of their allocated area.

In conclusion:
- Team A cleared the most.
- Team C cleared the least.