Xanthe Xanthe
  • 05-08-2024
  • Physics
College

An ultrasound machine uses [tex]$1.64 \times 10^5$[/tex] watts of power. If it draws [tex]$12.0 \, \text{A}$[/tex] of current, what is the resistance?

Answer :

sebassandin sebassandin
  • 16-04-2024

Answer:

R = 1138.9 Ω

Explanation:

Hello,

In this case, for the given power (P) and current (I), we can compute the resistance (R) via:

R = P / I²

Thus, we obtain:

R = 1.64x10⁵ W / (12.0 A)²

R = 1138.9 Ω

Best regards.

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