High School

An IV solution contains 5.10 g of glucose in 100.5 mL of water. What is the molarity of the solution? The molar mass of glucose is 180 g/mol.

Molarity: moles of solute / liters of solution

Answer :

molarity is defined as the number of moles of solute in 1 L of solvent
number of moles of glucose = mass of glucose present / molar mass of glucose
number of glucose moles = 5.10 g / 180 g/mol = 0.0283 mol
there are 0.0283 mol in 100.5 mL water
we need to find the number of glucose moles in 1000 mL
therefore in 1000 mL there are - 0.0283 mol / (100.5 x 10⁻³ L) = 0.282 mol/L
molality of solution - 0.282 M

Final answer:

The molarity of the solution is 0.279 M.

Explanation:

To find the molarity of the solution, we need to calculate the number of moles of glucose and the volume of the solution in liters. The molarity is defined as moles of solute per liter of solution.

First, we calculate the number of moles of glucose:

Moles of glucose = mass of glucose / molar mass of glucose

Moles of glucose = 5.10 g / 180 g/mol = 0.028 moles

Next, we calculate the volume of the solution in liters:

Volume of solution = 100.5 ml / 1000 = 0.1005 L

Finally, we plug in the values into the molarity formula:

Molarity = moles of glucose / volume of solution

Molarity = 0.028 moles / 0.1005 L = 0.279 M

Learn more about Molarity of a solution here:

https://brainly.com/question/18648803

#SPJ11