Answer :
Answer:
Part A:
Workers Needed=20.833≅21
Part B:
Productivity of individual worker=2.0833 parts/hour
Part C:
Multifactor productivity=0.0832 Parts/$
Explanation:
Part A:
Total parts =100,000
Workers needed= Total parts/(Parts per hour* hours per shift*Total Shifts)
[tex]Worker\ needed=\frac{100000}{10\ Parts/hour*8\ hours/shift*60\ shifts/worker} \\Workers\ needed= 20.833[/tex]
Workers needed=20.833≅21
Part B:
Productivity of individual worker:
[tex]Productivity\ of\ individual\ worker=\frac{100000}{100\ workers*8\ hours/shift*60\ shifts/worker} \\Productivity\ of\ individual\ worker=2.0833\ parts/hour[/tex]
Part C:
Total cost of material= $10*100,000=$1,000,000
Capital Costl= $100,000
Total labor Cost=[tex]21\ workers*8\ hours/shift*60\ shifts/worker*\$10/hour[/tex]
Total labor Cost=$100,800
Multifactor productivity=Total Parts/(Total cost of material+capital cost+Total labor Cost)
[tex]Multifactor\ productivity=\frac{100000}{\$1,000,000+\$100,000+\$100,800} \\ Multifactor\ productivity=0.08324\ Parts/\$[/tex]
Final answer:
The industrial plant needs approximately 21 workers per shift to meet its demand of 100,000 parts per month. An individual worker's productivity, if the shift consists of 100 workers, is 80 parts per worker-hour. The multifactor productivity, considering material, capital, and labor costs, is 0.048 parts per dollar.
Explanation:
In order to answer the questions related to the industrial plant's operations, we'll need to do a few calculations. For question a, we know that there are 20 workdays in a month and that each day consists of 3 shifts of 8 hours each. That is a total of 480 hours in a month. If the plant needs to produce 100,000 parts per month and a worker can produce 10 parts per hour, we'll need 100,000 / 10 = 10,000 worker hours. Thus, since there are 480 hours in a month, the plant would need 10,000 / 480 ≈ 21 workers per shift (rounded up).
For question b, if each shift has 100 workers, and each worker can produce 10 parts per hour for 8 hours, then each worker produces 80 parts in a shift, and the 100 workers together produce 8,000 parts per shift. If we again presume 60 shifts in a month (3 shifts per day for 20 days), then 60 shifts would produce 480,000 parts, which means the productivity of an individual worker is 480,000 parts per month divided by 6,000 worker hours, or 80 parts per worker hour.
Lastly, for question c, multifactor productivity represents the output per unit of combined inputs. The combined costs of material, capital, and labor here are (10 × 100,000) + 100,000 + (10 × 21 workers × 8 hours × 20 days × 3 shifts) = 2,104,000. Therefore, the multifactor productivity is 100,000 parts / 2,104,000 = 0.048 parts per dollar.
Learn more about Workforce Productivity here:
https://brainly.com/question/11535307
#SPJ3
