High School

An employee is exposed to a noise decibel level of:

- 110 dB for \( \frac{1}{4} \) hour
- 100 dB for \( \frac{1}{2} \) hour
- 90 dB for \( 1 \frac{1}{2} \) hours

The equivalent noise exposure:

A. \( \text{LEX,8} = 105.6 \, \text{dB} \)

B. \( \text{LEX,8} = 97.3 \, \text{dB} \)

C. \( \text{LEX,8} = 90.2 \, \text{dB} \)

D. \( \text{LEX,8} = 84.7 \, \text{dB} \)

Answer :

Final answer:

The equivalent noise exposure for the given scenario is approximately 97.3 dB.

Explanation:

To calculate the equivalent noise exposure for the given scenario, we need to use the concept of sound intensity level and the formula for calculating LEX,8. The formula is:

LEX,8 = 10 log10(T1*10(L1/10) + T2*10(L2/10) + T3*10(L3/10))

where T1, T2, and T3 are the time exposures in hours, and L1, L2, and L3 are the noise decibel levels for the respective time exposures.

Plugging in the given values, we can solve for LEX,8.

LEX,8 = 10 log10((1/4)*10(110/10) + (1/2)*10(100/10) + (3/2)*10(90/10))

LEX,8 ≈ 97.3 dB

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