Answer :
Final answer:
The amount of metal deposited in an electrolysis cell depends on the metal’s equivalent weight and the quantity of electricity passed through. The metal with the smallest equivalent weight will deposit the most mass from a 1.0 M solution.
Explanation:
The amount of metal deposited in an electrolysis cell depends on its equivalent weight and the current passed through the cell. Faraday's First Law of Electrolysis states that the mass of any substance deposited during electrolysis is proportional to the quantity of electricity passed through the cell. Given the current of 1.50 and time of 3000 s, we can calculate this quantity using the equation Q = It, where Q is the quantity of electricity, I is the current, and t is time. Now, from a 1.0 M solution, the metal that gets deposited the most would be the one with the smallest equivalent weight, as it requires less charge to deposit a greater mass of such a metal.
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