Answer :
Answer:
0.74
Step-by-step explanation:
An automobile manufacturer claims that its jeep has a 37.8 miles/gallon (MPG) rating.
Given that rating of a jeep is on an average 37.8 miles/gallon and std deviation is sq rt of 4.41
Sample size = 240
Sample mean = 37.9
Significant level = 2%
Mean difference = [tex]=37.9-37.8=0.10[/tex]
Std error of sample = [tex]\frac{s}{\sqrt{n} } =\frac{\sqrt{4.41} }{\sqrt{240} } \\=0.1356[/tex]
Test statistic = Mean diff/std error
= [tex]\frac{0.1}{0.1356}\\ =0.7378[/tex]
Test statistic = 0.74 (rounding off to two decimals)
