Answer :
Final answer:
The person ingested about 1.71 mEq of sodium after swallowing 36 tablets of NaF, each containing 2 mg of the compound.
Explanation:
The amount of sodium (Na) in one mole of sodium fluoride (NaF) can be calculated knowing that the molar mass of NaF is approximately 42 g/mol, and the molar mass of Na is approximately 23 g/mol. Sodium therefore constitutes about 23/42 of the mass in NaF, or 54.76%.
With each tablet containing 2 mg of NaF, 36 tablets would contain a total of 72 mg of NaF. Therefore, the amount of sodium ingested can be calculated as 72 mg * 54.76% = 39.43 mg.
To convert this to milliequivalents (mEq), we need to know that 1 mEq of sodium is equivalent to 23 mg (because the atomic mass of sodium is approximately 23). Therefore, 39.43 mg of sodium is equivalent to 1.71 mEq of sodium.
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