Answer :
A 84 kg man lying on a surface of negligible friction shoves a 88 g stone away from himself, giving it a speed of 4.6 m/s, the speed does the man acquire as a result is 0.48 m/s.
The man exerts a force on the stone, causing it to move. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. In this case, as the man pushes the stone away, the stone pushes the man in the opposite direction. To find the speed at which the man acquires, we can use the principle of conservation of momentum. The momentum before the shove is zero since both the man and the stone are initially at rest. After the shove, the momentum of the stone is given by the product of its mass and velocity: (88 g) * (4.6 m/s).
According to the law of conservation of momentum, the total momentum before the shove must be equal to the total momentum after the shove. Since the momentum of the stone is in one direction, the man must acquire an equal momentum in the opposite direction. Therefore, the man's momentum after the shove is also (88 g) * (4.6 m/s). To find the man's speed, we divide his momentum by his mass (84 kg).
Let's calculate: (88 g) * (4.6 m/s) / (84 kg) = 0.48 m/s.
Therefore, the man acquires a speed of 0.48 m/s as a result of shoving the stone.
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