College

After being cut off, Billy accelerates at a rate of [tex]12.3 \, \text{m/s}^2[/tex] for 455 meters. As he approaches the biker who cut him off, his velocity is 125 m/s.

What was his initial velocity?

A. 33.3 m/s
B. 66.6 m/s
C. 99.9 m/s
D. 122.2 m/s

Answer :

Answer:

The initial velocity of Billy is 66.6 m/s.

Explanation:

Given;

acceleration of Billy, a = 12.3 m/s²

distance moved by Billy, d = 455 m

final velocity of Billy, v = 125 m/s

let the initial velocity of Billy = u

Apply the following equation of motion;

v² = u² + 2ad

125² = u² + 2(12.3 x 455)

15625 = u² + 11193

u² = 15625 - 11193

u² = 4432

u = √4432

u = 66.57 m/s

u = 66.6 m/s.

Therefore, the initial velocity of Billy is 66.6 m/s.

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