High School

Add the following:

a. [tex]35 + (-14)[/tex]

b. [tex]-42 + (-20)[/tex]

c. [tex]18 + 32[/tex]

d. [tex]-28 + 14[/tex]

e. [tex]32 + (-14)[/tex]

f. [tex]-48 + (-44)[/tex]

Answer :

We will add each pair of numbers step by step:

1. For part (a):

We have
[tex]$$35 + (-14).$$[/tex]
Adding a negative number is the same as subtracting, so we compute:
[tex]$$35 - 14 = 21.$$[/tex]

2. For part (b):

We have
[tex]$$-42 + (-20).$$[/tex]
This is the same as subtracting:
[tex]$$-42 - 20 = -62.$$[/tex]

3. For part (c):

We have
[tex]$$18 + 32.$$[/tex]
Adding these two positive numbers gives:
[tex]$$18 + 32 = 50.$$[/tex]

4. For part (d):

We have
[tex]$$-28 + 14.$$[/tex]
You can think of this as subtracting 28 from 14:
[tex]$$14 - 28 = -14.$$[/tex]
Alternatively, you could view it as subtracting 14 from 28 and keeping the negative sign:
[tex]$$-28 + 14 = -14.$$[/tex]

5. For part (e):

We have
[tex]$$32 + (-14).$$[/tex]
This again is the same as subtracting:
[tex]$$32 - 14 = 18.$$[/tex]

6. For part (f):

We have
[tex]$$-48 + (-44).$$[/tex]
Adding two negative numbers means you add their absolute values and keep the negative sign:
[tex]$$48 + 44 = 92,$$[/tex]
so
[tex]$$-48 + (-44) = -92.$$[/tex]

Thus, the results for the six parts are:
[tex]$$
\begin{aligned}
\text{(a)}&\; 21, \\
\text{(b)}&\; -62, \\
\text{(c)}&\; 50, \\
\text{(d)}&\; -14, \\
\text{(e)}&\; 18, \\
\text{(f)}&\; -92.
\end{aligned}
$$[/tex]