Answer :
To find the number of games where the cost of playing at Adams Arcade equals the cost at Jims Jamming, we set up the equation 7.50 + 0.45x = 1.25x and solve for x. This gives us x = 9.375, so a person must play 10 games for the costs to be the same, when rounding to the nearest whole number.
To determine how many games need to be played for the total cost at Adams Arcade and Jims Jamming to be the same, we need to set up an equation where the total cost for both arcades is equal.
Let's denote the number of games played by x. At Adams Arcade, the cost would be the entrance fee plus the cost per game multiplied by the number of games: 7.50 + 0.45x.
At Jims Jamming, since there is no entrance fee, the cost is simply the cost per game multiplied by the number of games: 1.25x.
To find the number of games where both costs are the same, we set the two expressions equal to each other:
7.50 + 0.45x = 1.25x
Now, we solve for x:
0.45x - 1.25x = -7.50
-0.80x = -7.50
x = 7.50 / 0.80
x = 9.375
Since we cannot play a fraction of a game, we would round up to the nearest whole number. Thus, a person must play 10 games for the total cost to be the same at both arcades.
Answer:
Step-by-step explanation:
cost of playing x games at Adams = 7.50 + 0.45x
cost of playing x games at Jims = 1.25x
1.25x = 7.50 + 0.45x
1.25-0.45x = 7.50
0.80x = 7.50
x = 7.50/0.80 = 9.375 , but x must be an integer.
The cost is never the same. When x ≤ 9, Adams costs more. When x ≥ 10, Jims costs more.
