Answer :
The cooling rate required for partially condensing 66.9 mol of acetone vapor from a gas stream can be calculated by considering the heat transfer needed for the condensation process.
To find the cooling rate required for condensing acetone vapor from a gas stream, we need to consider the heat transfer involved in the condensation process. Acetone, a volatile liquid, can be condensed from its vapor phase by cooling the gas stream. The amount of heat removed from the gas stream during condensation determines the cooling rate needed.
The process of condensation involves converting the acetone vapor into liquid acetone by extracting heat from the gas stream. This heat transfer is governed by the principles of thermodynamics, specifically the latent heat of vaporization of acetone. The latent heat of vaporization is the amount of heat energy required to convert one mole of a substance from liquid to vapor at constant temperature.
In this scenario, we have 66.9 mol of acetone vapor to be condensed. The cooling rate required depends on the rate at which heat is removed from the gas stream to facilitate condensation. By calculating the amount of heat energy that needs to be extracted from the gas stream to condense 66.9 mol of acetone vapor, we can determine the cooling rate required for the process.
To calculate the cooling rate, we need to consider factors such as the initial temperature of the gas stream, the heat capacity of the gas mixture (including both acetone and nitrogen), and the heat transfer coefficient of the cooling medium (e.g., water or air). By applying the principles of heat transfer and thermodynamics, we can determine the cooling rate necessary to achieve partial condensation of acetone from the gas stream.
