College

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ A total of 2,000 square feet is to be enclosed in two pens, separated by a chain-link fence. The outside walls are to be constructed of brick. The brick wall costs $20 per linear foot, and the chain-link costs $4 per linear foot. Find the dimensions that minimize the construction cost.

Answer :

Answer:

Dimensions that minimize is; 20 ft x 100 ft

Step-by-step explanation:

Let the width and length be x and y respectively.

We are given area as 2000 Sq.ft.

Thus;

xy = 2000 - - - (eq 1)

We are told that the brick wall costs $20 per linear foot and the chain link costs $4 per linear foot. Thus;

C(x) = 20x + 4y

From eq(1),y = 2000/x

Thus;

C(x) = 20x + 4(2000/x)

C(x) = 20x + 8000/x

To minimize this, we will differentiate and equate to 0.

Thus;

C'(x) = 20 - 8000/x²

Equating to zeeo;

20 - 8000/x² = 0

20 = 8000/x²

20x² = 8000

Divide both sides by 20;

x² = 8000/20

x² = 400

x = √400

x = 20 ft

Putting 20 for x in eq 1,we have;

20y = 2000

y = 2000/20

y = 100 ft