A tensile test uses a test specimen with a gage length of 50 mm and an area of 213 mm². During the test, the specimen yields under a load of 95,514 N at a gage length of 50.3 mm, which corresponds to the 0.2 percent yield point. The maximum load of 169,438 N is reached at a gage length of 61 mm, and fracture occurs at a gage length of 70 mm. If the specimen necked to an area of 99.9 mm², determine the percent reduction in area. Enter your answer as a whole number, not as a fraction.

The percentage reduction in area for the test specimen after necking was calculated using the change in area divided by the initial area, multiplied by 100. The initial area was 213 mm², while the final area after necking was 99.9 mm². This led to an area reduction of approximately 53%.

Explanation:

The percentage reduction in area is calculated by the difference in initial and final areas divided by the initial area. This quantity is then multiplied by 100 to convert it to a percentage:

Percentage Reduction in Area = (Initial Area - Final Area) / Initial Area * 100

In this case, the initial area is 213 mm² and the final area after necking is 99.9 mm². Substituting these values into the formula gives:

Percentage Reduction in Area = (213 - 99.9) / 213 * 100

This equation simplifies to an approximated 52.82% when rounded down to the nearest whole percentage, the area reduction is 53%.

Learn more about Percentage Reduction in Area here:

https://brainly.com/question/34847026

#SPJ11