Answer :
Answer:
[tex]V_f=V_2=1.22\times 10^{-3} L=1.22mL[/tex]
Explanation:
Use Charles's law which states: "At constant pressure, the volume occupied by a gas sample is directly proportional to the absolute temperatures they support."
This law can be expressed mathematically as follows:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Where:
[tex]V_1=Initial\hspace{3}volume=1.64mL=1.64\times 10^{-3} L\\V_2=Final\hspace{3}volume\\T_1=Initial\hspace{3}temperature=94.6$^{\circ}$C=367.75K\\T_2=Final\hspace{3}temperature=0.3$^{\circ}$C=273.45K[/tex]
Solving for [tex]V_2[/tex]
[tex]V_2=\frac{V_1*T_2}{T_1} =\frac{(1.64\times 10^{-3} )*273.45}{367.75} =1.21946431\times 10^{-3} \approx1.22\times 10^{-3} L =1.22mL[/tex]
