Answer :
The tension in the cable pulling the stuntman, which equals the frictional force due to kinetic friction and is calculated using the coefficient of kinetic friction and the normal force, is 735.44 N.
Calculating the Tension in the Cable
To calculate the tension in the cable, we need to use the concept of kinetic friction and Newton's Second Law. Since the stuntman is moving at a constant velocity, the net force acting on him is zero. This implies that the tension in the cable must be equal to the frictional force opposing the motion. The frictional force can be calculated using the coefficient of kinetic friction and the normal force. The normal force in this case is simply the weight of the stuntman due to gravity.
The formula for frictional force [tex](F_f)[/tex] is:
[tex]F_f = ext{coefficient of kinetic friction} \timesimes ext{normal force}[/tex]
To find the normal force, which is the force opposing the weight of the stuntman:
[tex]N = m \timesimes g[/tex]
where m is the mass of the stuntman and g is the acceleration due to gravity (9.8 m/s²). Substituting the values we get:
[tex]N = 98.2 kg \timesimes 9.8 m/s² = 962.36 N[/tex]
Now, the frictional force is given by:
[tex]F_f = 0.764 \timesimes 962.36[/tex]
N = 735.44 N
Since the tension in the cable must balance this frictional force to maintain constant velocity, the tension is also 735.44 N.
