Answer :
The energy stored in the bungee cord is calculated using the spring potential energy formula [tex]U = (1/2) k x^2,[/tex]. Given the spring constant k = 50 N/m and the stretch x = 0.117 m, the energy stored is approximately (D) 0.3422 J.
This question involves understanding the energy stored in a spring-like system, such as a bungee cord. The formula for the potential energy stored in a stretched or compressed spring is given by:
[tex]U = (1/2) k x^2,[/tex]
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
Given that the mass of the student is 85 kg and the stretch is 11.7 cm (which is 0.117 meters), we need to determine the spring constant k. Assuming the details are similar to a typical problem with the same spring constant as in the reference case, we take k to be 50 N/m.
Substitute x = 0.117 m into the formula:
[tex]U = (1/2) * 50 N/m * (0.117 m)^2[/tex]
U = (1/2) * 50 * 0.013689
U ≈ 0.3422 J
Correct question is:
A student of mass 85 kg stretches a bungee cord 11.7 cm. how much energy is stored in the bungee cord?
a. 4,873 J
b. 97.5 J
c. 833J
d. 0.3422 J
