A student is asked to measure 30.0 g of methanol (density = 0.7914 g/mL at 25˚C) but has only a graduated cylinder with which to measure it. What volume of methanol should the student use to obtain the required 30.0 g?

A. 23.7 mL
B. 30.0 mL
C. 32.4 mL
D. 37.9 mL

To obtain 30.0 g of methanol with a given density 0.7914 g/mL, the student needs to use approximately 37.9 mL of methanol when measured using a graduated cylinder.

Explanation:

Given that the mass of methanol (CH3OH) is 30.0 g and the density (d) is 0.7914 g/mL, the student is asked to calculate the corresponding volume. The formula to calculate volume is Volume (V) = Mass (m) / Density (d). Substituting the given mass and density values gives V = 30.0 g / 0.7914 g/mL which results in the volume of methanol to be approximately 37.9 mL. So the student needs to use 37.9 mL of methanol to obtain the required 30.0 g.

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A student is asked to measure 30.0 g of methanol (density = 0.7914 g/mL at 25˚C) but has only a graduated cylinder with which to measure it. What volume of methanol should the student use to obtain the required 30.0 g? A. 23.7 mL B. 30.0 mL C. 32.4 mL D. 37.9 mL

Answer :

Final answer:

Explanation:

Other Questions

A student is asked to measure 30.0 g of methanol (density = 0.7914 g/mL at 25˚C) but has only a graduated cylinder with which to measure it. What volume of methanol should the student use to obtain the required 30.0 g?

A. 23.7 mL
B. 30.0 mL
C. 32.4 mL
D. 37.9 mL