High School

A steel ball of mass 139 kg is attached to a thin (massless) cable and whirled around in a circle in a vertical plane. The circle has a radius of 1.16 m. When it is at the bottom of the circle, the ball has a speed of 13.3 m/s. Calculate the magnitude of the tension in the cable when the mass is at the bottom of the circle.

Answer :

The tension in the cable when the mass is at the bottom of the circle is about 2,907 N.

To calculate the magnitude of the tension in the cable when the mass is at the bottom of the circle, you need to use the formula for net force which includes gravitational force and centripetal force.

After substituting the given values into the formula, the result is approximately 2,907 N. This is due to the combined force of gravity and the inertia of the ball at the bottom of the circle.

Let's do the calculations: F = 139 kg * 9.8 m/s²(gravitational acceleration) + 139 kg *(13.3 m/s)² / 1.16 m. After processing the operations, the result for the tension is approximately 2,907 N.

This question belongs to the Physics domain specifically the topic of circular motion. To find the magnitude of the tension in the cable when the mass is at the bottom of the circle, we need to use the formula for net force acting on the ball, which in this case consists of gravitational force and centripetal force. The equation for the net force (F) is: F = m*g + m*v²/r.

The explanation behind this is that the tension in the string is highest at the bottom of the circular motion due to the combined force of gravity and the inertia of the ball trying to continue in a straight line.

In conclusion, the tension in the cable when the mass is at the bottom of the circle is about 2,907 N.

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