Answer :
Answer
The magnitude of the short free span is approximately 0.00875 meters.
Given:
Factored load = 8 kPa
Alpha coefficient (α) = 250
Factored moment = 17.5 kNm/m
The short free span of a slab refers to the distance between supports where the moments and deflections are relatively small.
To find the short free span, we can use the formula:
Short free span (L) = (Factored moment / (Alpha coefficient * Factored load))
Substituting the given values:
L = (17.5 kNm/m) / (250 * 8 kPa)
First, we need to convert kNm to kN·m:
1 kNm = 1 kN·m
Next, we need to convert kPa to kN/m²:
1 kPa = 1 kN/m²
L = (17.5 kN·m/m) / (250 * 8 kN/m²)
L = 17.5 / (250 * 8)
L ≈ 0.00875 m
Therefore, the magnitude of the short free span is approximately 0.00875 meters.
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