Answer :
Final answer:
In this arithmetic sequence that starts at 91 and subtracts 3 repeatedly, the first four terms of the sequence are 91, 88, 85, and 82.
Explanation:
The subject of this question is arithmetic sequences in Mathematics. An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is constant. In this particular sequence, we start at 91 and subtract 3 each time to get the next term. So, the first term ('a1') of the sequence is 91, to find the next term ('a2'), we subtract 3 from the first term, getting 88. As per same rule, 'a3' will be 85 and 'a4' will be 82. Therefore, the first four terms of the sequence are 91, 88, 85, 82.
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