Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ A sample of solid iodine is heated with an electrical coil. If 48.8 J is added to a 10.4-gram sample and the final temperature is 35.9 ∘C, calculate the initial temperature of the iodine.

Answer: _____ ∘C.

To calculate the initial temperature of the iodine, use the equation q = mcΔT. Substitute the given values and solve for T. The initial temperature of the iodine is 28.54°C.

Explanation:

To calculate the initial temperature of the iodine, we can use the equation:

q = mcΔT

Where q is the heat added, m is the mass of the iodine, c is the specific heat capacity of iodine, and ΔT is the change in temperature. In this case, we are given q = 48.8J, m = 10.4g, and ΔT = 35.9°C - T, where T is the initial temperature. The specific heat capacity of iodine is 0.214J/g°C. Substituting these values into the equation:

48.8J = (10.4g)(0.214J/g°C)(35.9°C - T)

Simplifying the equation:

T = 28.54°C

Therefore, the initial temperature of the iodine is 28.54°C.

Learn more about Calculating initial temperature of a substance here:

https://brainly.com/question/29216312

#SPJ11