Answer :
Final answer:
To find the pressure of pure oxygen in a mixture of oxygen and steam, you subtract the pressure of water (23.8 Torr) from the total pressure (760 Torr) to get 736.2 Torr. After rounding, the pressure of pure oxygen is 736 Torr. Therefore the correct answer is option b.
Explanation:
The pressure of the pure oxygen can be found using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas in the mixture. In this case, we are given the total pressure of the gas mixture (760 Torr) and the pressure of gaseous water (steam) which is 23.8 Torr. To find the pressure of pure oxygen, we subtract the pressure of the gaseous water from the total pressure.
Total pressure = Pressure of oxygen + Pressure of water
Therefore, Pressure of oxygen = Total pressure - Pressure of water
Pressure of oxygen = 760 Torr - 23.8 Torr
= 736.2 Torr
After rounding to the nearest whole number, the pressure of the pure oxygen is 736 Torr, which corresponds with answer choice B.
