High School

A sample of 76 body temperatures has a mean of 98.3 °F. Assume that the standard deviation is known to be 0.5 °F. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.5 °F, as is commonly believed.

What is the value of the test statistic for this test? (Round the answer to two decimal places.)

Answer :

The test statistic for testing the claim of a population mean body temperature of 98.5 °F is approximately -0.169.

The value of the test statistic for testing the claim that the mean body temperature of the population is equal to 98.5 °F can be determined using the formula:

Test statistic
=
Sample mean

Population mean
Standard deviation
/
Sample size
Test statistic=
Standard deviation/
Sample size


Sample mean−Population mean



In this case, the sample mean is 98.3 °F, the population mean is 98.5 °F (as claimed), the standard deviation is 0.5 °F, and the sample size is 76. Plugging these values into the formula, we can calculate the test statistic.

Test statistic = (98.3 - 98.5) / (0.5 / sqrt(76)) ≈ -0.169

The test statistic is approximately -0.169 (rounded to two decimal places).

The test statistic measures the difference between the sample mean and the hypothesized population mean, in terms of the standard deviation and sample size. A negative test statistic indicates that the sample mean is slightly lower than the claimed population mean. By comparing this test statistic with critical values from the t-distribution at a 0.05 significance level, we can determine whether the difference is statistically significant or simply due to chance.

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