A saline solution contains 1.00 g of NaCl (molar mass = 58.55 g/mol) in 97.0 mL of solution. Calculate the concentration of NaCl in this solution in units of molarity.

a) 0.52 M
b) 1.03 M
c) 1.55 M
d) 2.04 M

The molarity of a solution is calculated by dividing the moles of solute by the volume of solution in liters. In this case, we are given that the solution contains 1.00 g of NaCl in 97.0 ml of solution. To calculate the moles of NaCl, we divide the mass of NaCl by its molar mass. Then, we convert the volume of solution to liters. Finally, we divide the moles of NaCl by the volume of solution in liters to obtain the concentration of NaCl in units of molarity. The result is approximately 2.04 M.

A saline solution contains 1.00 g of NaCl (molar mass = 58.55 g/mol) in 97.0 mL of solution. Calculate the concentration of NaCl in this solution in units of molarity.a) 0.52 M b) 1.03 M c) 1.55 M d) 2.04 M

Answer :

Final answer:

Explanation:

Other Questions

A saline solution contains 1.00 g of NaCl (molar mass = 58.55 g/mol) in 97.0 mL of solution. Calculate the concentration of NaCl in this solution in units of molarity.

a) 0.52 M
b) 1.03 M
c) 1.55 M
d) 2.04 M