Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ A roller coaster with a potential energy of [tex]$235,200 \, J$[/tex] sits at the top of a 30 m high hill. What is the mass of the roller coaster? (Use the formula: [tex]PE = mgh[/tex])

A. 800 kg
B. [tex]7,840 \, kg[/tex]
C. [tex]8,000 \, kg[/tex]
D. [tex]78,400 \, kg[/tex]

We start with the formula for gravitational potential energy:

$$
PE = mgh
$$

Given:
- Potential energy, $PE = 235\,200 \, \text{J}$,
- Height, $h = 30 \, \text{m}$,
- Acceleration due to gravity, $g = 9.8 \, \text{m/s}^2$.

First, calculate the product $g \times h$:

$$
g \times h = 9.8 \times 30 = 294 \, \text{m}^2/\text{s}^2
$$

Now, solve for the mass $m$ by rearranging the formula:

$$
m = \frac{PE}{g \times h} = \frac{235\,200}{294}
$$

Performing the division gives:

$$
m = 800 \, \text{kg}
$$

Thus, the mass of the roller coaster is $800 \, \text{kg}$.