Answer :
The total force exerted on the rock is [tex]376 N[/tex] east, which includes overcoming any resistive forces, and the calculated force needed for the given acceleration confirms the correctness.
To determine the Total Force exerted on the rock, we need to sum the forces applied by both men. Since both forces are applied in the same direction (east), we can directly add them together:
First man's force: [tex]156 N[/tex] east .
Second man's force: [tex]220 N[/tex] east.
Total Force = [tex]156 N + 220 N = 376 N[/tex] east.
Given the rock's acceleration of [tex]0.2 m/s^2[/tex], we verify this using Newton's Second Law, [tex]F = ma[/tex] :
Mass of the rock, [tex]m = 710 kg[/tex].
Acceleration, [tex]a = 0.2 m/s^2[/tex].
Total Force, [tex]F = 710 kg \times 0.2 m/s^2 = 142 N[/tex].
The calculated force to achieve the given acceleration is [tex]142 N[/tex] , which indicates that the total exerted force of [tex]376 N[/tex] not only moves the rock but also overcomes other resistive forces like friction.
The total force exerted on the rock is 376 Newtons east.
To find the total force exerted on the rock, we need to consider the individual forces and their directions.
The first man pushes with a force of 156 Newtons east. We can represent this force as a vector: (156 N, 0 N).
The second man pushes with a force of 220 Newtons east. Similarly, we represent this force as a vector: (220 N, 0 N).
Since both forces are in the same direction (east), we can simply add the magnitudes of the forces to find the total force exerted:
Total force = 156 N + 220 N = 376 N
Therefore, the total force exerted on the rock is 376 Newtons east.
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