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------------------------------------------------ A robot pushes a 50 kg box with a forward force of 394 N. The box is opposed by 94 N of friction.

Answer :

Final answer:

The force of friction opposing the motion can be found by subtracting the applied force from the total force acting on the box.

Explanation:

The force of friction opposing the motion can be found by subtracting the applied force from the total force acting on the box. In this case, the total force is the sum of the applied force and the force of friction.

Total force = Applied force + Force of friction

Total force = 394N + (-94N)

Total force = 300N

Therefore, the force of friction opposing the motion is 300N.

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