Answer :
Question:
A regular pentagon is dilated by a scale factor of 7/3 to create a new pentagon. How does the perimeter of the new pentagon compare with the original perimeter?
Answer:
The perimeter of the new pentagon is equal to [tex]\frac{7}{3}[/tex] times the perimeter of the original pentagon
Solution:
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
Let
,
z is the scale factor
x is the perimeter of the new pentagon
y is the perimeter of the original pentagon
Then,
Scale factor = ratio of perimeters
[tex]z=\frac{x}{y}[/tex]
In this problem we have
[tex]z=\frac{7}{3}[/tex]
Substituting we get,
[tex]\frac{7}{3} = \frac{x}{y}\\\\x = \frac{7}{3}y[/tex]
Which means,
[tex]perimeter\ of\ the\ new\ pentagon = \frac{7}{3} \times \text{ perimeter of the original pentagon}[/tex]
Therefore
, the perimeter of the new pentagon is equal to [tex]\frac{7}{3}[/tex] times the perimeter of the original pentagon
