High School

A rectangle has an area of [tex]8x^6 y^7 - 6x^5 y^5[/tex] square units. If one of the dimensions is [tex]2x^3 y^4[/tex] units, what is the other dimension?

Show your work.

Answer :

Final answer:

To find the other dimension of the rectangle, divide the area (8x^6 y^7 - 6x^5 y^5) by the given dimension (2x^3 y^4). The resulting dimension is 4x^3 y^3 - 3x^2 y units.

Explanation:

To find the other dimension of a rectangle when given the area and one dimension, we divide the area by the known dimension. In this case, the area of the rectangle is given as 8x6 y7 - 6x5 y5 units, and one of the dimensions is 2x3 y4 units. Dividing the area by this dimension will give us the other dimension.

To do this, we can set up the expression:
(8x6 y7 - 6x5 y5)/(2x3 y4)

Performing the division term by term:

  • 8x6 y7 / 2x3 y4 = 4x(6-3) y(7-4) = 4x3 y3
  • - 6x5 y5 / 2x3 y4 = -3x(5-3) y(5-4) = -3x2 y

So the other dimension of the rectangle is 4x3 y3 - 3x2 y units.

Learn more about rectangle dimensions here:

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