High School

A race car travels 99 m/s around a circular track of radius 52 m. What is the magnitude of the resultant force on the 1900 kg driver and his car if the car does not slip?

Answer in units of kN.

Answer :

Final answer:

The magnitude of the resultant force on the race car and driver is 357.375 kN.

Explanation:

First, we need to find the centripetal acceleration of the race car traveling around the circular track. The centripetal acceleration can be found using the formula:

a = v² / r

where v is the velocity of the car and r is the radius of the circular track. Plugging in the values, we get:

a = (99 m/s)² / 52 m = 188.25 m/s²

Next, we can use Newton's second law of motion to find the magnitude of the resultant force acting on the car. The formula is:

F = m * a

where F is the force, m is the mass of the car, and a is the centripetal acceleration. Plugging in the values, we get:

F = (1900 kg) * (188.25 m/s²) = 357,375 N

Finally, we can convert the force to kilonewtons (kN) by dividing by 1000:

F = 357,375 N / 1000 = 357.375 kN

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