College

A pool is 57.4 m long and 35.8 m wide. If the average depth of water is 5.70 ft, what is the mass (in kg) of the water in the pool?

Enter your answer in scientific notation. The density of water is 1.0 g/mL.

Answer :

Final answer:

The mass of the water in the pool is calculated by finding the volume (length*width*depth) and then multiplying by the density of the water. The final result is 3.93 x 10^7 kg in scientific notation which is the mass of the water in the pool.

Explanation:

In this problem, we are trying to find the mass of the water in a pool with a given length, width, depth and water density. It's important to note that 1 meter equals 3.281 feet and 1 kilogram is equivalent to 1000 grams.

The volume of the pool is 57.4m * 35.8m * (5.7ft * 0.3048 m/ft) = 39326.06928 cubic meters. Each cubic meter contains 1,000,000 milliliters, so the total volume is 3.932606928 x 10^10 mL. With the density of water given as 1.0 g/mL, the mass of the water in the pool is thus 3.932606928 x 10^10 g.

To convert this into kilograms, remember that 1 kilogram = 1000 grams so the mass in kg is 3.932606928 x 10^7 kg. Therefore, the mass of water in the pool is 3.93 x 10^7 kg (to two decimal places, in scientific notation).

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