Answer :
Final answer:
The mass of the water in the pool is calculated by finding the volume (length*width*depth) and then multiplying by the density of the water. The final result is 3.93 x 10^7 kg in scientific notation which is the mass of the water in the pool.
Explanation:
In this problem, we are trying to find the mass of the water in a pool with a given length, width, depth and water density. It's important to note that 1 meter equals 3.281 feet and 1 kilogram is equivalent to 1000 grams.
The volume of the pool is 57.4m * 35.8m * (5.7ft * 0.3048 m/ft) = 39326.06928 cubic meters. Each cubic meter contains 1,000,000 milliliters, so the total volume is 3.932606928 x 10^10 mL. With the density of water given as 1.0 g/mL, the mass of the water in the pool is thus 3.932606928 x 10^10 g.
To convert this into kilograms, remember that 1 kilogram = 1000 grams so the mass in kg is 3.932606928 x 10^7 kg. Therefore, the mass of water in the pool is 3.93 x 10^7 kg (to two decimal places, in scientific notation).
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